Solve 2.8x+1.1y-5.3=0

$$2.8x+1.1y-5.3=0$$

Solve for x

$$x=\frac{53-11y}{28}$$

Steps for Solving Linear Equation

Subtract 1.1y from both sides. Anything subtracted from zero gives its negation.

$$2.8x-5.3=-1.1y$$

Add 5.3 to both sides.

$$2.8x=-1.1y+5.3$$

The equation is in standard form.

$$2.8x=\frac{53-11y}{10}$$

Divide both sides of the equation by 2.8, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{2.8x}{2.8}=\frac{53-11y}{2.8\times 10}$$

Dividing by 2.8 undoes the multiplication by 2.8.

$$x=\frac{53-11y}{2.8\times 10}$$

Divide \frac{-11y+53}{10} by 2.8 by multiplying \frac{-11y+53}{10} by the reciprocal of 2.8.

$$x=\frac{53-11y}{28}$$

Solve for y

$$y=\frac{53-28x}{11}$$

Steps for Solving Linear Equation

Subtract 2.8x from both sides. Anything subtracted from zero gives its negation.

$$1.1y-5.3=-2.8x$$

Add 5.3 to both sides.

$$1.1y=-2.8x+5.3$$

The equation is in standard form.

$$1.1y=-\frac{14x}{5}+5.3$$

Divide both sides of the equation by 1.1, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{1.1y}{1.1}=\frac{-\frac{14x}{5}+5.3}{1.1}$$

Dividing by 1.1 undoes the multiplication by 1.1.

$$y=\frac{-\frac{14x}{5}+5.3}{1.1}$$

Divide -\frac{14x}{5}+5.3 by 1.1 by multiplying -\frac{14x}{5}+5.3 by the reciprocal of 1.1.

$$y=\frac{53-28x}{11}$$