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Solve for V_A
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2.6-1=\frac{0.1V_{A}^{2}\times 1}{1}
Multiply 0.1 and 10 to get 1.
1.6=\frac{0.1V_{A}^{2}\times 1}{1}
Subtract 1 from 2.6 to get 1.6.
1.6=0.1V_{A}^{2}
Cancel out 1 and 1.
0.1V_{A}^{2}=1.6
Swap sides so that all variable terms are on the left hand side.
V_{A}^{2}=\frac{1.6}{0.1}
Divide both sides by 0.1.
V_{A}^{2}=16
Expand \frac{1.6}{0.1} by multiplying both numerator and the denominator by 10. Anything divided by one gives itself.
V_{A}=4 V_{A}=-4
Take the square root of both sides of the equation.
2.6-1=\frac{0.1V_{A}^{2}\times 1}{1}
Multiply 0.1 and 10 to get 1.
1.6=\frac{0.1V_{A}^{2}\times 1}{1}
Subtract 1 from 2.6 to get 1.6.
1.6=0.1V_{A}^{2}
Cancel out 1 and 1.
0.1V_{A}^{2}=1.6
Swap sides so that all variable terms are on the left hand side.
0.1V_{A}^{2}-1.6=0
Subtract 1.6 from both sides.
V_{A}=\frac{0±\sqrt{0^{2}-4\times 0.1\left(-1.6\right)}}{2\times 0.1}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 0.1 for a, 0 for b, and -1.6 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
V_{A}=\frac{0±\sqrt{-4\times 0.1\left(-1.6\right)}}{2\times 0.1}
Square 0.
V_{A}=\frac{0±\sqrt{-0.4\left(-1.6\right)}}{2\times 0.1}
Multiply -4 times 0.1.
V_{A}=\frac{0±\sqrt{0.64}}{2\times 0.1}
Multiply -0.4 times -1.6 by multiplying numerator times numerator and denominator times denominator. Then reduce the fraction to lowest terms if possible.
V_{A}=\frac{0±\frac{4}{5}}{2\times 0.1}
Take the square root of 0.64.
V_{A}=\frac{0±\frac{4}{5}}{0.2}
Multiply 2 times 0.1.
V_{A}=4
Now solve the equation V_{A}=\frac{0±\frac{4}{5}}{0.2} when ± is plus.
V_{A}=-4
Now solve the equation V_{A}=\frac{0±\frac{4}{5}}{0.2} when ± is minus.
V_{A}=4 V_{A}=-4
The equation is now solved.