Solve 2.6(1+x)^2=3.146

$$2.6 ( 1 + x ) ^ { 2 } = 3.146$$

Solve for x

$$x=0.1$$

$$x=-2.1$$

Steps by Finding Square Root

Divide both sides of the equation by 2.6, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{2.6\left(x+1\right)^{2}}{2.6}=\frac{3.146}{2.6}$$

Dividing by 2.6 undoes the multiplication by 2.6.

$$\left(x+1\right)^{2}=\frac{3.146}{2.6}$$

Divide 3.146 by 2.6 by multiplying 3.146 by the reciprocal of 2.6.

$$\left(x+1\right)^{2}=1.21$$

Take the square root of both sides of the equation.

$$x+1=\frac{11}{10} x+1=-\frac{11}{10}$$

Subtract 1 from both sides of the equation.

$$x+1-1=\frac{11}{10}-1 x+1-1=-\frac{11}{10}-1$$

Subtracting 1 from itself leaves 0.

$$x=\frac{11}{10}-1 x=-\frac{11}{10}-1$$

Subtract 1 from \frac{11}{10}.

$$x=\frac{1}{10}$$

Subtract 1 from -\frac{11}{10}.

$$x=-\frac{21}{10}$$

The equation is now solved.

$$x=\frac{1}{10} x=-\frac{21}{10}$$