Solve 2.5^2+[(6-3/4)div2]*2^5

$$2.5 ^ { 2 } + [ ( 6 - \frac { 3 } { 4 } ) \div 2 ] \times 2 ^ { 5 }$$

Evaluate

$$90.25$$

Solution Steps

Calculate 2.5 to the power of 2 and get 6.25.

$$6.25+\frac{6-\frac{3}{4}}{2}\times 2^{5}$$

Convert 6 to fraction \frac{24}{4}.

$$6.25+\frac{\frac{24}{4}-\frac{3}{4}}{2}\times 2^{5}$$

Since \frac{24}{4} and \frac{3}{4} have the same denominator, subtract them by subtracting their numerators.

$$6.25+\frac{\frac{24-3}{4}}{2}\times 2^{5}$$

Subtract 3 from 24 to get 21.

$$6.25+\frac{\frac{21}{4}}{2}\times 2^{5}$$

Express \frac{\frac{21}{4}}{2} as a single fraction.

$$6.25+\frac{21}{4\times 2}\times 2^{5}$$

Multiply 4 and 2 to get 8.

$$6.25+\frac{21}{8}\times 2^{5}$$

Calculate 2 to the power of 5 and get 32.

$$6.25+\frac{21}{8}\times 32$$

Express \frac{21}{8}\times 32 as a single fraction.

$$6.25+\frac{21\times 32}{8}$$

Multiply 21 and 32 to get 672.

$$6.25+\frac{672}{8}$$

Divide 672 by 8 to get 84.

$$6.25+84$$

Add 6.25 and 84 to get 90.25.

$$90.25$$

Factor

$$\frac{19 ^ {2}}{2 ^ {2}} = 90\frac{1}{4} = 90.25$$