Solve 2(x+2)=4/5(68-x)

$$2(x+2)= \frac{ 4 }{ 5 } (68-x)$$

Solve for x

$$x=18$$

Steps for Solving Linear Equation

Use the distributive property to multiply 2 by x+2.

$$2x+4=\frac{4}{5}\left(68-x\right)$$

Use the distributive property to multiply \frac{4}{5} by 68-x.

$$2x+4=\frac{4}{5}\times 68+\frac{4}{5}\left(-1\right)x$$

Express \frac{4}{5}\times 68 as a single fraction.

$$2x+4=\frac{4\times 68}{5}+\frac{4}{5}\left(-1\right)x$$

Multiply 4 and 68 to get 272.

$$2x+4=\frac{272}{5}+\frac{4}{5}\left(-1\right)x$$

Multiply \frac{4}{5} and -1 to get -\frac{4}{5}.

$$2x+4=\frac{272}{5}-\frac{4}{5}x$$

Add \frac{4}{5}x to both sides.

$$2x+4+\frac{4}{5}x=\frac{272}{5}$$

Combine 2x and \frac{4}{5}x to get \frac{14}{5}x.

$$\frac{14}{5}x+4=\frac{272}{5}$$

Subtract 4 from both sides.

$$\frac{14}{5}x=\frac{272}{5}-4$$

Convert 4 to fraction \frac{20}{5}.

$$\frac{14}{5}x=\frac{272}{5}-\frac{20}{5}$$

Since \frac{272}{5} and \frac{20}{5} have the same denominator, subtract them by subtracting their numerators.

$$\frac{14}{5}x=\frac{272-20}{5}$$

Subtract 20 from 272 to get 252.

$$\frac{14}{5}x=\frac{252}{5}$$

Multiply both sides by \frac{5}{14}, the reciprocal of \frac{14}{5}.

$$x=\frac{252}{5}\times \frac{5}{14}$$

Multiply \frac{252}{5} times \frac{5}{14} by multiplying numerator times numerator and denominator times denominator.

$$x=\frac{252\times 5}{5\times 14}$$

Cancel out 5 in both numerator and denominator.

$$x=\frac{252}{14}$$

Divide 252 by 14 to get 18.

$$x=18$$