Solve 2(x+1)-3(x2)=x+6

$$2(x+1)-3(x2)=x+6$$

Solve for x

$$x=3x_{2}+4$$

Solution Steps

Use the distributive property to multiply 2 by x+1.

$$2x+2-3x_{2}=x+6$$

Subtract x from both sides.

$$2x+2-3x_{2}-x=6$$

Combine 2x and -x to get x.

$$x+2-3x_{2}=6$$

Subtract 2 from both sides.

$$x-3x_{2}=6-2$$

Subtract 2 from 6 to get 4.

$$x-3x_{2}=4$$

Add 3x_{2} to both sides.

$$x=4+3x_{2}$$

Solve for x_2

$$x_{2}=\frac{x-4}{3}$$

Steps for Solving Linear Equation

Use the distributive property to multiply 2 by x+1.

$$2x+2-3x_{2}=x+6$$

Subtract 2x from both sides.

$$2-3x_{2}=x+6-2x$$

Combine x and -2x to get -x.

$$2-3x_{2}=-x+6$$

Subtract 2 from both sides.

$$-3x_{2}=-x+6-2$$

Subtract 2 from 6 to get 4.

$$-3x_{2}=-x+4$$

The equation is in standard form.

$$-3x_{2}=4-x$$

Divide both sides by -3.

$$\frac{-3x_{2}}{-3}=\frac{4-x}{-3}$$

Dividing by -3 undoes the multiplication by -3.

$$x_{2}=\frac{4-x}{-3}$$

Divide -x+4 by -3.

$$x_{2}=\frac{x-4}{3}$$