Solve 2(4(7+4(5*3-19))-3(40-8))

$$2(4(7+4(5 \times 3-19))-3(40-8))$$

Evaluate

$$-264$$

Solution Steps

Multiply 5 and 3 to get 15.

$$2\left(4\left(7+4\left(15-19\right)\right)-3\left(40-8\right)\right)$$

Subtract 19 from 15 to get -4.

$$2\left(4\left(7+4\left(-4\right)\right)-3\left(40-8\right)\right)$$

Multiply 4 and -4 to get -16.

$$2\left(4\left(7-16\right)-3\left(40-8\right)\right)$$

Subtract 16 from 7 to get -9.

$$2\left(4\left(-9\right)-3\left(40-8\right)\right)$$

Multiply 4 and -9 to get -36.

$$2\left(-36-3\left(40-8\right)\right)$$

Subtract 8 from 40 to get 32.

$$2\left(-36-3\times 32\right)$$

Multiply 3 and 32 to get 96.

$$2\left(-36-96\right)$$

Subtract 96 from -36 to get -132.

$$2\left(-132\right)$$

Multiply 2 and -132 to get -264.

$$-264$$

Factor

$$-264$$