Solve 2(3x-4)+5(6x-7)-7x=16(x+15)-10

$$2(3x-4)+5(6x-7)-7x=16(x+15)-10$$

Solve for x

$$x=21$$

Steps for Solving Linear Equation

Use the distributive property to multiply 2 by 3x-4.

$$6x-8+5\left(6x-7\right)-7x=16\left(x+15\right)-10$$

Use the distributive property to multiply 5 by 6x-7.

$$6x-8+30x-35-7x=16\left(x+15\right)-10$$

Combine 6x and 30x to get 36x.

$$36x-8-35-7x=16\left(x+15\right)-10$$

Subtract 35 from -8 to get -43.

$$36x-43-7x=16\left(x+15\right)-10$$

Combine 36x and -7x to get 29x.

$$29x-43=16\left(x+15\right)-10$$

Use the distributive property to multiply 16 by x+15.

$$29x-43=16x+240-10$$

Subtract 10 from 240 to get 230.

$$29x-43=16x+230$$

Subtract 16x from both sides.

$$29x-43-16x=230$$

Combine 29x and -16x to get 13x.

$$13x-43=230$$

Add 43 to both sides.

$$13x=230+43$$

Add 230 and 43 to get 273.

$$13x=273$$

Divide both sides by 13.

$$x=\frac{273}{13}$$

Divide 273 by 13 to get 21.

$$x=21$$