Solve 2(3x(2-4)+2x-5(x+1))=-28

$$2(3x(2-4)+2x-5(x+1))=-28$$

Solve for x

$$x=1$$

Steps for Solving Linear Equation

Divide both sides by 2.

$$3x\left(2-4\right)+2x-5\left(x+1\right)=\frac{-28}{2}$$

Divide -28 by 2 to get -14.

$$3x\left(2-4\right)+2x-5\left(x+1\right)=-14$$

Subtract 4 from 2 to get -2.

$$3x\left(-2\right)+2x-5\left(x+1\right)=-14$$

Multiply 3 and -2 to get -6.

$$-6x+2x-5\left(x+1\right)=-14$$

Combine -6x and 2x to get -4x.

$$-4x-5\left(x+1\right)=-14$$

Use the distributive property to multiply -5 by x+1.

$$-4x-5x-5=-14$$

Combine -4x and -5x to get -9x.

$$-9x-5=-14$$

Add 5 to both sides.

$$-9x=-14+5$$

Add -14 and 5 to get -9.

$$-9x=-9$$

Divide both sides by -9.

$$x=\frac{-9}{-9}$$

Divide -9 by -9 to get 1.

$$x=1$$