Solve 2(-3*2+3)-2*2^2(2*2-3)

$$2(-3 \times 2+3)-2 \times { 2 }^{ 2 } (2 \times 2-3)$$

Evaluate

$$-14$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 1 and 2 to get 3.

$$2\left(-3\times 2+3\right)-2^{3}\left(2\times 2-3\right)$$

Multiply -3 and 2 to get -6.

$$2\left(-6+3\right)-2^{3}\left(2\times 2-3\right)$$

Add -6 and 3 to get -3.

$$2\left(-3\right)-2^{3}\left(2\times 2-3\right)$$

Multiply 2 and -3 to get -6.

$$-6-2^{3}\left(2\times 2-3\right)$$

Calculate 2 to the power of 3 and get 8.

$$-6-8\left(2\times 2-3\right)$$

Multiply 2 and 2 to get 4.

$$-6-8\left(4-3\right)$$

Subtract 3 from 4 to get 1.

$$-6-8\times 1$$

Multiply 8 and 1 to get 8.

$$-6-8$$

Subtract 8 from -6 to get -14.

$$-14$$

Factor

$$-14$$