Solve 2({left(-3/2right)}^2+6(-3/2)+3

$$2( { \left( \frac{ -3 }{ 2 } \right) }^{ 2 } +6(- \frac{ 3 }{ 2 } )+3$$

Evaluate

$$-\frac{15}{2}=-7.5$$

Solution Steps

Fraction \frac{-3}{2} can be rewritten as -\frac{3}{2} by extracting the negative sign.

$$2\left(\left(-\frac{3}{2}\right)^{2}+6\left(-\frac{3}{2}\right)+3\right)$$

Calculate -\frac{3}{2} to the power of 2 and get \frac{9}{4}.

$$2\left(\frac{9}{4}+6\left(-\frac{3}{2}\right)+3\right)$$

Multiply 6 and -\frac{3}{2} to get -9.

$$2\left(\frac{9}{4}-9+3\right)$$

Subtract 9 from \frac{9}{4} to get -\frac{27}{4}.

$$2\left(-\frac{27}{4}+3\right)$$

Add -\frac{27}{4} and 3 to get -\frac{15}{4}.

$$2\left(-\frac{15}{4}\right)$$

Multiply 2 and -\frac{15}{4} to get -\frac{15}{2}.

$$-\frac{15}{2}$$

Factor

$$-\frac{15}{2} = -7\frac{1}{2} = -7.5$$