Solve 2,5*10^-8+40*10^-11

$$2,5 \cdot 10 ^ { - 8 } + 40 \cdot 10 ^ { - 11 }$$

Evaluate

$$0,0000000254$$

Solution Steps

Calculate 10 to the power of -8 and get \frac{1}{100000000}.

$$2,5\times \frac{1}{100000000}+40\times 10^{-11}$$

Multiply 2,5 and \frac{1}{100000000} to get \frac{1}{40000000}.

$$\frac{1}{40000000}+40\times 10^{-11}$$

Calculate 10 to the power of -11 and get \frac{1}{100000000000}.

$$\frac{1}{40000000}+40\times \frac{1}{100000000000}$$

Multiply 40 and \frac{1}{100000000000} to get \frac{1}{2500000000}.

$$\frac{1}{40000000}+\frac{1}{2500000000}$$

Add \frac{1}{40000000} and \frac{1}{2500000000} to get \frac{127}{5000000000}.

$$\frac{127}{5000000000}$$

Factor

$$\frac{127}{2 ^ {9} \cdot 5 ^ {10}} = 2.54 \times 10^{-8}$$