Solve 2+(2*+1)*(2*-1)=left(2*-3right)^2+4

$$2+(2 \times +1) \times (2 \times -1)= { \left(2 \times -3 \right) }^{ 2 } +4$$

Verify

Solution Steps

Multiply 2 and 1 to get 2.

$$2+2\times 2\left(-1\right)=\left(2\left(-3\right)\right)^{2}+4$$

Multiply 2 and 2 to get 4.

$$2+4\left(-1\right)=\left(2\left(-3\right)\right)^{2}+4$$

Multiply 4 and -1 to get -4.

$$2-4=\left(2\left(-3\right)\right)^{2}+4$$

Subtract 4 from 2 to get -2.

$$-2=\left(2\left(-3\right)\right)^{2}+4$$

Multiply 2 and -3 to get -6.

$$-2=\left(-6\right)^{2}+4$$

Calculate -6 to the power of 2 and get 36.

$$-2=36+4$$

Add 36 and 4 to get 40.

$$-2=40$$

Compare -2 and 40.

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