Solve 2+3+23^2/2=44*2-3/2^2

$$2+ \frac{ 3+ { 23 }^{ 2 } }{ 2 } =44 \times 2- \frac{ 3 }{ { 2 }^{ 2 } }$$

Verify

Solution Steps

Multiply both sides of the equation by 2.

$$4+3+23^{2}=88\times 2-\frac{1}{2}\times 3$$

Add 4 and 3 to get 7.

$$7+23^{2}=88\times 2-\frac{1}{2}\times 3$$

Calculate 23 to the power of 2 and get 529.

$$7+529=88\times 2-\frac{1}{2}\times 3$$

Add 7 and 529 to get 536.

$$536=88\times 2-\frac{1}{2}\times 3$$

Multiply 88 and 2 to get 176.

$$536=176-\frac{1}{2}\times 3$$

Express -\frac{1}{2}\times 3 as a single fraction.

$$536=176+\frac{-3}{2}$$

Fraction \frac{-3}{2} can be rewritten as -\frac{3}{2} by extracting the negative sign.

$$536=176-\frac{3}{2}$$

Convert 176 to fraction \frac{352}{2}.

$$536=\frac{352}{2}-\frac{3}{2}$$

Since \frac{352}{2} and \frac{3}{2} have the same denominator, subtract them by subtracting their numerators.

$$536=\frac{352-3}{2}$$

Subtract 3 from 352 to get 349.

$$536=\frac{349}{2}$$

Convert 536 to fraction \frac{1072}{2}.

$$\frac{1072}{2}=\frac{349}{2}$$

Compare \frac{1072}{2} and \frac{349}{2}.

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