Solve 2+3/6*3-7+12*2=

$$2+ \frac{ 3 }{ 6 \cdot 3 } -7+12 \cdot 2=$$

Evaluate

$$\frac{115}{6}\approx 19.166666667$$

Solution Steps

Multiply 6 and 3 to get 18.

$$2+\frac{3}{18}-7+12\times 2$$

Reduce the fraction \frac{3}{18} to lowest terms by extracting and canceling out 3.

$$2+\frac{1}{6}-7+12\times 2$$

Convert 2 to fraction \frac{12}{6}.

$$\frac{12}{6}+\frac{1}{6}-7+12\times 2$$

Since \frac{12}{6} and \frac{1}{6} have the same denominator, add them by adding their numerators.

$$\frac{12+1}{6}-7+12\times 2$$

Add 12 and 1 to get 13.

$$\frac{13}{6}-7+12\times 2$$

Convert 7 to fraction \frac{42}{6}.

$$\frac{13}{6}-\frac{42}{6}+12\times 2$$

Since \frac{13}{6} and \frac{42}{6} have the same denominator, subtract them by subtracting their numerators.

$$\frac{13-42}{6}+12\times 2$$

Subtract 42 from 13 to get -29.

$$-\frac{29}{6}+12\times 2$$

Multiply 12 and 2 to get 24.

$$-\frac{29}{6}+24$$

Convert 24 to fraction \frac{144}{6}.

$$-\frac{29}{6}+\frac{144}{6}$$

Since -\frac{29}{6} and \frac{144}{6} have the same denominator, add them by adding their numerators.

$$\frac{-29+144}{6}$$

Add -29 and 144 to get 115.

$$\frac{115}{6}$$

Factor

$$\frac{5 \cdot 23}{2 \cdot 3} = 19\frac{1}{6} = 19.166666666666668$$