Solve 2+-2/1.50.5*1

$$2+ \frac{ -2 }{ 1.5 } 0.5 \cdot 1$$

Evaluate

$$\frac{4}{3}\approx 1.333333333$$

Solution Steps

Expand \frac{-2}{1.5} by multiplying both numerator and the denominator by 10.

$$2+\frac{-20}{15}\times 0.5\times 1$$

Reduce the fraction \frac{-20}{15} to lowest terms by extracting and canceling out 5.

$$2-\frac{4}{3}\times 0.5$$

Convert decimal number 0.5 to fraction \frac{5}{10}. Reduce the fraction \frac{5}{10} to lowest terms by extracting and canceling out 5.

$$2-\frac{4}{3}\times \frac{1}{2}$$

Multiply -\frac{4}{3} times \frac{1}{2} by multiplying numerator times numerator and denominator times denominator.

$$2+\frac{-4}{3\times 2}\times 1$$

Do the multiplications in the fraction \frac{-4}{3\times 2}.

$$2+\frac{-4}{6}\times 1$$

Reduce the fraction \frac{-4}{6} to lowest terms by extracting and canceling out 2.

$$2-\frac{2}{3}$$

Convert 2 to fraction \frac{6}{3}.

$$\frac{6}{3}-\frac{2}{3}$$

Since \frac{6}{3} and \frac{2}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{6-2}{3}$$

Subtract 2 from 6 to get 4.

$$\frac{4}{3}$$

Factor

$$\frac{2 ^ {2}}{3} = 1\frac{1}{3} = 1.3333333333333333$$