Factor
2\left(z-5\right)\left(z^{2}+5z+25\right)
Evaluate
2\left(z^{3}-125\right)
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2\left(z^{3}-125\right)
Factor out 2.
\left(z-5\right)\left(z^{2}+5z+25\right)
Consider z^{3}-125. Rewrite z^{3}-125 as z^{3}-5^{3}. The difference of cubes can be factored using the rule: a^{3}-b^{3}=\left(a-b\right)\left(a^{2}+ab+b^{2}\right).
2\left(z-5\right)\left(z^{2}+5z+25\right)
Rewrite the complete factored expression. Polynomial z^{2}+5z+25 is not factored since it does not have any rational roots.
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