Solve for x
x=\frac{1}{3}+\frac{\sqrt{2}}{2y_{1}}
y_{1}\neq 0
Solve for y_1
y_{1}=\frac{3\sqrt{2}}{2\left(3x-1\right)}
x\neq \frac{1}{3}
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2y_{1}x-\frac{2}{3}y_{1}-\sqrt{2}=0
Use the distributive property to multiply 2y_{1} by x-\frac{1}{3}.
2y_{1}x-\sqrt{2}=\frac{2}{3}y_{1}
Add \frac{2}{3}y_{1} to both sides. Anything plus zero gives itself.
2y_{1}x=\frac{2}{3}y_{1}+\sqrt{2}
Add \sqrt{2} to both sides.
2y_{1}x=\frac{2y_{1}}{3}+\sqrt{2}
The equation is in standard form.
\frac{2y_{1}x}{2y_{1}}=\frac{\frac{2y_{1}}{3}+\sqrt{2}}{2y_{1}}
Divide both sides by 2y_{1}.
x=\frac{\frac{2y_{1}}{3}+\sqrt{2}}{2y_{1}}
Dividing by 2y_{1} undoes the multiplication by 2y_{1}.
x=\frac{1}{3}+\frac{\sqrt{2}}{2y_{1}}
Divide \frac{2y_{1}}{3}+\sqrt{2} by 2y_{1}.
2y_{1}x-\frac{2}{3}y_{1}-\sqrt{2}=0
Use the distributive property to multiply 2y_{1} by x-\frac{1}{3}.
2y_{1}x-\frac{2}{3}y_{1}=\sqrt{2}
Add \sqrt{2} to both sides. Anything plus zero gives itself.
\left(2x-\frac{2}{3}\right)y_{1}=\sqrt{2}
Combine all terms containing y_{1}.
\frac{\left(2x-\frac{2}{3}\right)y_{1}}{2x-\frac{2}{3}}=\frac{\sqrt{2}}{2x-\frac{2}{3}}
Divide both sides by 2x-\frac{2}{3}.
y_{1}=\frac{\sqrt{2}}{2x-\frac{2}{3}}
Dividing by 2x-\frac{2}{3} undoes the multiplication by 2x-\frac{2}{3}.
y_{1}=\frac{3\sqrt{2}}{2\left(3x-1\right)}
Divide \sqrt{2} by 2x-\frac{2}{3}.
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