Solve for x
x=\frac{8y-28}{3}
Solve for y
y=\frac{3x}{8}+\frac{7}{2}
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-\frac{3}{4}x=7-2y
Subtract 2y from both sides.
\frac{-\frac{3}{4}x}{-\frac{3}{4}}=\frac{7-2y}{-\frac{3}{4}}
Divide both sides of the equation by -\frac{3}{4}, which is the same as multiplying both sides by the reciprocal of the fraction.
x=\frac{7-2y}{-\frac{3}{4}}
Dividing by -\frac{3}{4} undoes the multiplication by -\frac{3}{4}.
x=\frac{8y-28}{3}
Divide 7-2y by -\frac{3}{4} by multiplying 7-2y by the reciprocal of -\frac{3}{4}.
2y=7+\frac{3}{4}x
Add \frac{3}{4}x to both sides.
2y=\frac{3x}{4}+7
The equation is in standard form.
\frac{2y}{2}=\frac{\frac{3x}{4}+7}{2}
Divide both sides by 2.
y=\frac{\frac{3x}{4}+7}{2}
Dividing by 2 undoes the multiplication by 2.
y=\frac{3x}{8}+\frac{7}{2}
Divide 7+\frac{3x}{4} by 2.
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