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2y-\frac{1}{3}+\frac{2}{3}y=2
Add \frac{2}{3}y to both sides.
\frac{8}{3}y-\frac{1}{3}=2
Combine 2y and \frac{2}{3}y to get \frac{8}{3}y.
\frac{8}{3}y=2+\frac{1}{3}
Add \frac{1}{3} to both sides.
\frac{8}{3}y=\frac{6}{3}+\frac{1}{3}
Convert 2 to fraction \frac{6}{3}.
\frac{8}{3}y=\frac{6+1}{3}
Since \frac{6}{3} and \frac{1}{3} have the same denominator, add them by adding their numerators.
\frac{8}{3}y=\frac{7}{3}
Add 6 and 1 to get 7.
y=\frac{7}{3}\times \frac{3}{8}
Multiply both sides by \frac{3}{8}, the reciprocal of \frac{8}{3}.
y=\frac{7\times 3}{3\times 8}
Multiply \frac{7}{3} times \frac{3}{8} by multiplying numerator times numerator and denominator times denominator.
y=\frac{7}{8}
Cancel out 3 in both numerator and denominator.