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y^{2}\left(2y-1\right)-\left(2y-1\right)
Do the grouping 2y^{3}-y^{2}-2y+1=\left(2y^{3}-y^{2}\right)+\left(-2y+1\right), and factor out y^{2} in the first and -1 in the second group.
\left(2y-1\right)\left(y^{2}-1\right)
Factor out common term 2y-1 by using distributive property.
\left(y-1\right)\left(y+1\right)
Consider y^{2}-1. Rewrite y^{2}-1 as y^{2}-1^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).
\left(y-1\right)\left(2y-1\right)\left(y+1\right)
Rewrite the complete factored expression.