Solve 2y^2-4x+4=0

$$2 y ^ { 2 } - 4 x + 4 = 0$$

Solve for x

$$x=\frac{y^{2}+2}{2}$$

Steps for Solving Linear Equation

Subtract 2y^{2} from both sides. Anything subtracted from zero gives its negation.

$$-4x+4=-2y^{2}$$

Subtract 4 from both sides.

$$-4x=-2y^{2}-4$$

Divide both sides by -4.

$$\frac{-4x}{-4}=\frac{-2y^{2}-4}{-4}$$

Dividing by -4 undoes the multiplication by -4.

$$x=\frac{-2y^{2}-4}{-4}$$

Divide -2y^{2}-4 by -4.

$$x=\frac{y^{2}}{2}+1$$

Solve for y (complex solution)

$$y=-\sqrt{2\left(x-1\right)}$$

$$y=\sqrt{2\left(x-1\right)}$$

Solve for y

$$y=\sqrt{2\left(x-1\right)}$$

$$y=-\sqrt{2\left(x-1\right)}\text{, }x\geq 1$$