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2y^{2}-y>0
Subtract y from both sides.
y\left(2y-1\right)>0
Factor out y.
y<0 y-\frac{1}{2}<0
For the product to be positive, y and y-\frac{1}{2} have to be both negative or both positive. Consider the case when y and y-\frac{1}{2} are both negative.
y<0
The solution satisfying both inequalities is y<0.
y-\frac{1}{2}>0 y>0
Consider the case when y and y-\frac{1}{2} are both positive.
y>\frac{1}{2}
The solution satisfying both inequalities is y>\frac{1}{2}.
y<0\text{; }y>\frac{1}{2}
The final solution is the union of the obtained solutions.