Solve 2y^2=150

$$2 y ^ { 2 } = 150$$

Solve for y

$$y=5\sqrt{3}\approx 8.660254038$$

$$y=-5\sqrt{3}\approx -8.660254038$$

Steps by Finding Square Root

Divide both sides by 2.

$$y^{2}=\frac{150}{2}$$

Divide 150 by 2 to get 75.

$$y^{2}=75$$

Take the square root of both sides of the equation.

$$y=5\sqrt{3} y=-5\sqrt{3}$$

Steps Using the Quadratic Formula

Divide both sides by 2.

$$y^{2}=\frac{150}{2}$$

Divide 150 by 2 to get 75.

$$y^{2}=75$$

Subtract 75 from both sides.

$$y^{2}-75=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -75 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$y=\frac{0±\sqrt{0^{2}-4\left(-75\right)}}{2}$$

Square 0.

$$y=\frac{0±\sqrt{-4\left(-75\right)}}{2}$$

Multiply -4 times -75.

$$y=\frac{0±\sqrt{300}}{2}$$

Take the square root of 300.

$$y=\frac{0±10\sqrt{3}}{2}$$

Now solve the equation y=\frac{0±10\sqrt{3}}{2} when ± is plus.

$$y=5\sqrt{3}$$

Now solve the equation y=\frac{0±10\sqrt{3}}{2} when ± is minus.

$$y=-5\sqrt{3}$$

The equation is now solved.

$$y=5\sqrt{3} y=-5\sqrt{3}$$