Solve for y
y=\frac{x^{2}}{2}+x+1
Solve for x (complex solution)
x=\sqrt{2y-1}-1
x=-\sqrt{2y-1}-1
Solve for x
x=\sqrt{2y-1}-1
x=-\sqrt{2y-1}-1\text{, }y\geq \frac{1}{2}
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2y=x^{2}+2x+2
The equation is in standard form.
\frac{2y}{2}=\frac{x^{2}+2x+2}{2}
Divide both sides by 2.
y=\frac{x^{2}+2x+2}{2}
Dividing by 2 undoes the multiplication by 2.
y=\frac{x^{2}}{2}+x+1
Divide x^{2}+2x+2 by 2.
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