Solve for y
y=\frac{1}{2e^{x}}
Solve for x (complex solution)
x=-\ln(y)-2\pi n_{1}i-\ln(2)
n_{1}\in \mathrm{Z}
y\neq 0
Solve for x
x=-\left(\ln(y)+\ln(2)\right)
y>0
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2y=\frac{1}{e^{x}}
The equation is in standard form.
\frac{2y}{2}=\frac{1}{2e^{x}}
Divide both sides by 2.
y=\frac{1}{2e^{x}}
Dividing by 2 undoes the multiplication by 2.
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