Solve for x
x=\frac{8-2y}{3}
Solve for y
y=-\frac{3x}{2}+4
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8-3x=2y
Swap sides so that all variable terms are on the left hand side.
-3x=2y-8
Subtract 8 from both sides.
\frac{-3x}{-3}=\frac{2y-8}{-3}
Divide both sides by -3.
x=\frac{2y-8}{-3}
Dividing by -3 undoes the multiplication by -3.
x=\frac{8-2y}{3}
Divide -8+2y by -3.
2y=8-3x
The equation is in standard form.
\frac{2y}{2}=\frac{8-3x}{2}
Divide both sides by 2.
y=\frac{8-3x}{2}
Dividing by 2 undoes the multiplication by 2.
y=-\frac{3x}{2}+4
Divide 8-3x by 2.
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