Solve for x_1
x_{1}=\frac{4-2y}{3}
Solve for y
y=-\frac{3x_{1}}{2}+2
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3x_{1}-4=-2y
Subtract 2y from both sides. Anything subtracted from zero gives its negation.
3x_{1}=-2y+4
Add 4 to both sides.
3x_{1}=4-2y
The equation is in standard form.
\frac{3x_{1}}{3}=\frac{4-2y}{3}
Divide both sides by 3.
x_{1}=\frac{4-2y}{3}
Dividing by 3 undoes the multiplication by 3.
2y-4=-3x_{1}
Subtract 3x_{1} from both sides. Anything subtracted from zero gives its negation.
2y=-3x_{1}+4
Add 4 to both sides.
2y=4-3x_{1}
The equation is in standard form.
\frac{2y}{2}=\frac{4-3x_{1}}{2}
Divide both sides by 2.
y=\frac{4-3x_{1}}{2}
Dividing by 2 undoes the multiplication by 2.
y=-\frac{3x_{1}}{2}+2
Divide -3x_{1}+4 by 2.
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