Solve for x
x=\frac{2y}{9}+\frac{1}{3}
Solve for y
y=\frac{9x-3}{2}
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9x=2y+3
Swap sides so that all variable terms are on the left hand side.
\frac{9x}{9}=\frac{2y+3}{9}
Divide both sides by 9.
x=\frac{2y+3}{9}
Dividing by 9 undoes the multiplication by 9.
x=\frac{2y}{9}+\frac{1}{3}
Divide 2y+3 by 9.
2y=9x-3
Subtract 3 from both sides.
\frac{2y}{2}=\frac{9x-3}{2}
Divide both sides by 2.
y=\frac{9x-3}{2}
Dividing by 2 undoes the multiplication by 2.
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
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Limits
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