Solve for x
x=\frac{15-5y}{2}
Solve for y
y=-\frac{2x}{5}+3
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\frac{4}{5}x=6-2y
Subtract 2y from both sides.
\frac{\frac{4}{5}x}{\frac{4}{5}}=\frac{6-2y}{\frac{4}{5}}
Divide both sides of the equation by \frac{4}{5}, which is the same as multiplying both sides by the reciprocal of the fraction.
x=\frac{6-2y}{\frac{4}{5}}
Dividing by \frac{4}{5} undoes the multiplication by \frac{4}{5}.
x=\frac{15-5y}{2}
Divide 6-2y by \frac{4}{5} by multiplying 6-2y by the reciprocal of \frac{4}{5}.
2y=6-\frac{4}{5}x
Subtract \frac{4}{5}x from both sides.
2y=-\frac{4x}{5}+6
The equation is in standard form.
\frac{2y}{2}=\frac{-\frac{4x}{5}+6}{2}
Divide both sides by 2.
y=\frac{-\frac{4x}{5}+6}{2}
Dividing by 2 undoes the multiplication by 2.
y=-\frac{2x}{5}+3
Divide 6-\frac{4x}{5} by 2.
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