Solve 2xy+3=6x

$$2 x y + 3 = 6 x$$

Solve for x

$$x=-\frac{3}{2\left(y-3\right)}$$

$$y\neq 3$$

Steps for Solving Linear Equation

Subtract 6x from both sides.

$$2xy+3-6x=0$$

Subtract 3 from both sides. Anything subtracted from zero gives its negation.

$$2xy-6x=-3$$

Combine all terms containing x.

$$\left(2y-6\right)x=-3$$

Divide both sides by 2y-6.

$$\frac{\left(2y-6\right)x}{2y-6}=-\frac{3}{2y-6}$$

Dividing by 2y-6 undoes the multiplication by 2y-6.

$$x=-\frac{3}{2y-6}$$

Divide -3 by 2y-6.

$$x=-\frac{3}{2\left(y-3\right)}$$

Solve for y

$$y=3-\frac{3}{2x}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Subtract 3 from both sides.

$$2xy=6x-3$$

Divide both sides by 2x.

$$\frac{2xy}{2x}=\frac{6x-3}{2x}$$

Dividing by 2x undoes the multiplication by 2x.

$$y=\frac{6x-3}{2x}$$

Divide 6x-3 by 2x.

$$y=3-\frac{3}{2x}$$