Solve 2x2-8x=-5

$$2 x 2 - 8 x = - 5$$

Solve for x

$$x=\frac{x_{2}}{4}+\frac{5}{8}$$

Steps for Solving Linear Equation

Subtract 2x_{2} from both sides.

$$-8x=-5-2x_{2}$$

The equation is in standard form.

$$-8x=-2x_{2}-5$$

Divide both sides by -8.

$$\frac{-8x}{-8}=\frac{-2x_{2}-5}{-8}$$

Dividing by -8 undoes the multiplication by -8.

$$x=\frac{-2x_{2}-5}{-8}$$

Divide -5-2x_{2} by -8.

$$x=\frac{x_{2}}{4}+\frac{5}{8}$$

Solve for x_2

$$x_{2}=4x-\frac{5}{2}$$

Steps for Solving Linear Equation

Add 8x to both sides.

$$2x_{2}=-5+8x$$

The equation is in standard form.

$$2x_{2}=8x-5$$

Divide both sides by 2.

$$\frac{2x_{2}}{2}=\frac{8x-5}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$x_{2}=\frac{8x-5}{2}$$

Divide -5+8x by 2.

$$x_{2}=4x-\frac{5}{2}$$