Solve 2x-y+3=0

$$2 x - y + 3 = 0$$

Solve for x

$$x=\frac{y-3}{2}$$

Steps for Solving Linear Equation

Add y to both sides. Anything plus zero gives itself.

$$2x+3=y$$

Subtract 3 from both sides.

$$2x=y-3$$

Divide both sides by 2.

$$\frac{2x}{2}=\frac{y-3}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$x=\frac{y-3}{2}$$

Solve for y

$$y=2x+3$$

Steps for Solving Linear Equation

Subtract 2x from both sides. Anything subtracted from zero gives its negation.

$$-y+3=-2x$$

Subtract 3 from both sides.

$$-y=-2x-3$$

Divide both sides by -1.

$$\frac{-y}{-1}=\frac{-2x-3}{-1}$$

Dividing by -1 undoes the multiplication by -1.

$$y=\frac{-2x-3}{-1}$$

Divide -2x-3 by -1.

$$y=2x+3$$