Solve for x
x=\frac{7y}{2}+4
Solve for y
y=\frac{2\left(x-4\right)}{7}
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2x=8+7y
Add 7y to both sides.
2x=7y+8
The equation is in standard form.
\frac{2x}{2}=\frac{7y+8}{2}
Divide both sides by 2.
x=\frac{7y+8}{2}
Dividing by 2 undoes the multiplication by 2.
x=\frac{7y}{2}+4
Divide 8+7y by 2.
-7y=8-2x
Subtract 2x from both sides.
\frac{-7y}{-7}=\frac{8-2x}{-7}
Divide both sides by -7.
y=\frac{8-2x}{-7}
Dividing by -7 undoes the multiplication by -7.
y=\frac{2x-8}{7}
Divide 8-2x by -7.
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