Solve 2x-7y+8=0

$$2 x - 7 y + 8 = 0$$

Solve for x

$$x=\frac{7y}{2}-4$$

Steps for Solving Linear Equation

Add 7y to both sides. Anything plus zero gives itself.

$$2x+8=7y$$

Subtract 8 from both sides.

$$2x=7y-8$$

Divide both sides by 2.

$$\frac{2x}{2}=\frac{7y-8}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$x=\frac{7y-8}{2}$$

Divide 7y-8 by 2.

$$x=\frac{7y}{2}-4$$

Solve for y

$$y=\frac{2\left(x+4\right)}{7}$$

Steps for Solving Linear Equation

Subtract 2x from both sides. Anything subtracted from zero gives its negation.

$$-7y+8=-2x$$

Subtract 8 from both sides.

$$-7y=-2x-8$$

Divide both sides by -7.

$$\frac{-7y}{-7}=\frac{-2x-8}{-7}$$

Dividing by -7 undoes the multiplication by -7.

$$y=\frac{-2x-8}{-7}$$

Divide -2x-8 by -7.

$$y=\frac{2x+8}{7}$$