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2x-3=3y
Add 3y to both sides. Anything plus zero gives itself.
2x=3y+3
Add 3 to both sides.
\frac{2x}{2}=\frac{3y+3}{2}
Divide both sides by 2.
x=\frac{3y+3}{2}
Dividing by 2 undoes the multiplication by 2.
-3y-3=-2x
Subtract 2x from both sides. Anything subtracted from zero gives its negation.
-3y=-2x+3
Add 3 to both sides.
-3y=3-2x
The equation is in standard form.
\frac{-3y}{-3}=\frac{3-2x}{-3}
Divide both sides by -3.
y=\frac{3-2x}{-3}
Dividing by -3 undoes the multiplication by -3.
y=\frac{2x}{3}-1
Divide -2x+3 by -3.