Solve for x
x=\frac{3\left(y+3\right)}{2}
Solve for y
y=\frac{2x}{3}-3
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2x=9+3y
Add 3y to both sides.
2x=3y+9
The equation is in standard form.
\frac{2x}{2}=\frac{3y+9}{2}
Divide both sides by 2.
x=\frac{3y+9}{2}
Dividing by 2 undoes the multiplication by 2.
-3y=9-2x
Subtract 2x from both sides.
\frac{-3y}{-3}=\frac{9-2x}{-3}
Divide both sides by -3.
y=\frac{9-2x}{-3}
Dividing by -3 undoes the multiplication by -3.
y=\frac{2x}{3}-3
Divide 9-2x by -3.
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