Solve for x
x=\frac{3y}{2}+4
Solve for y
y=\frac{2\left(x-4\right)}{3}
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2x=8+3y
Add 3y to both sides.
2x=3y+8
The equation is in standard form.
\frac{2x}{2}=\frac{3y+8}{2}
Divide both sides by 2.
x=\frac{3y+8}{2}
Dividing by 2 undoes the multiplication by 2.
x=\frac{3y}{2}+4
Divide 8+3y by 2.
-3y=8-2x
Subtract 2x from both sides.
\frac{-3y}{-3}=\frac{8-2x}{-3}
Divide both sides by -3.
y=\frac{8-2x}{-3}
Dividing by -3 undoes the multiplication by -3.
y=\frac{2x-8}{3}
Divide 8-2x by -3.
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