Solve for x
x=\frac{3y}{2}-10
Solve for y
y=\frac{2\left(x+10\right)}{3}
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2x=-20+3y
Add 3y to both sides.
2x=3y-20
The equation is in standard form.
\frac{2x}{2}=\frac{3y-20}{2}
Divide both sides by 2.
x=\frac{3y-20}{2}
Dividing by 2 undoes the multiplication by 2.
x=\frac{3y}{2}-10
Divide -20+3y by 2.
-3y=-20-2x
Subtract 2x from both sides.
-3y=-2x-20
The equation is in standard form.
\frac{-3y}{-3}=\frac{-2x-20}{-3}
Divide both sides by -3.
y=\frac{-2x-20}{-3}
Dividing by -3 undoes the multiplication by -3.
y=\frac{2x+20}{3}
Divide -20-2x by -3.
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