Solve for x
x=\frac{3y-13}{2}
Solve for y
y=\frac{2x+13}{3}
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2x+13=3y
Add 3y to both sides. Anything plus zero gives itself.
2x=3y-13
Subtract 13 from both sides.
\frac{2x}{2}=\frac{3y-13}{2}
Divide both sides by 2.
x=\frac{3y-13}{2}
Dividing by 2 undoes the multiplication by 2.
-3y+13=-2x
Subtract 2x from both sides. Anything subtracted from zero gives its negation.
-3y=-2x-13
Subtract 13 from both sides.
\frac{-3y}{-3}=\frac{-2x-13}{-3}
Divide both sides by -3.
y=\frac{-2x-13}{-3}
Dividing by -3 undoes the multiplication by -3.
y=\frac{2x+13}{3}
Divide -2x-13 by -3.
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