Solve for x
x>2
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2x-3-\frac{1}{2}x>0
Subtract \frac{1}{2}x from both sides.
\frac{3}{2}x-3>0
Combine 2x and -\frac{1}{2}x to get \frac{3}{2}x.
\frac{3}{2}x>3
Add 3 to both sides. Anything plus zero gives itself.
x>3\times \frac{2}{3}
Multiply both sides by \frac{2}{3}, the reciprocal of \frac{3}{2}. Since \frac{3}{2} is positive, the inequality direction remains the same.
x>2
Cancel out 3 and 3.
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Limits
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