Solve for x
x=-\frac{z}{2}+y+3
Solve for y
y=\frac{z}{2}+x-3
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2x+z=6+2y
Add 2y to both sides.
2x=6+2y-z
Subtract z from both sides.
2x=2y-z+6
The equation is in standard form.
\frac{2x}{2}=\frac{2y-z+6}{2}
Divide both sides by 2.
x=\frac{2y-z+6}{2}
Dividing by 2 undoes the multiplication by 2.
x=-\frac{z}{2}+y+3
Divide 6+2y-z by 2.
-2y+z=6-2x
Subtract 2x from both sides.
-2y=6-2x-z
Subtract z from both sides.
-2y=6-z-2x
The equation is in standard form.
\frac{-2y}{-2}=\frac{6-z-2x}{-2}
Divide both sides by -2.
y=\frac{6-z-2x}{-2}
Dividing by -2 undoes the multiplication by -2.
y=\frac{z}{2}+x-3
Divide 6-2x-z by -2.
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Limits
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