Solve 2x(-2+i)^2+3-i=0

$$2 x ( - 2 + i ) ^ { 2 } + 3 - i = 0$$

Solve for x

$$x=-\frac{13}{50}-\frac{9}{50}i=-0.26-0.18i$$

Steps for Solving Linear Equation

Calculate -2+i to the power of 2 and get 3-4i.

$$2x\left(3-4i\right)+3-i=0$$

Multiply 2 and 3-4i to get 6-8i.

$$\left(6-8i\right)x+3-i=0$$

Subtract 3 from both sides. Anything subtracted from zero gives its negation.

$$\left(6-8i\right)x-i=-3$$

Add i to both sides.

$$\left(6-8i\right)x=-3+i$$

Divide both sides by 6-8i.

$$x=\frac{-3+i}{6-8i}$$

Multiply both numerator and denominator of \frac{-3+i}{6-8i} by the complex conjugate of the denominator, 6+8i.

$$x=\frac{\left(-3+i\right)\left(6+8i\right)}{\left(6-8i\right)\left(6+8i\right)}$$

Do the multiplications in \frac{\left(-3+i\right)\left(6+8i\right)}{\left(6-8i\right)\left(6+8i\right)}.

$$x=\frac{-26-18i}{100}$$

Divide -26-18i by 100 to get -\frac{13}{50}-\frac{9}{50}i.

$$x=-\frac{13}{50}-\frac{9}{50}i$$