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2x\left(x^{2}-4\right)-3\left(x^{2}-4\right)
Do the grouping 2x^{3}-8x-3x^{2}+12=\left(2x^{3}-8x\right)+\left(-3x^{2}+12\right), and factor out 2x in the first and -3 in the second group.
\left(x^{2}-4\right)\left(2x-3\right)
Factor out common term x^{2}-4 by using distributive property.
\left(x-2\right)\left(x+2\right)
Consider x^{2}-4. Rewrite x^{2}-4 as x^{2}-2^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).
\left(2x-3\right)\left(x-2\right)\left(x+2\right)
Rewrite the complete factored expression.