Solve for y
y=\frac{2\left(x^{3}-2\right)}{3x}
x\neq 0
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-3xy=4-2x^{3}
Subtract 2x^{3} from both sides.
\left(-3x\right)y=4-2x^{3}
The equation is in standard form.
\frac{\left(-3x\right)y}{-3x}=\frac{4-2x^{3}}{-3x}
Divide both sides by -3x.
y=\frac{4-2x^{3}}{-3x}
Dividing by -3x undoes the multiplication by -3x.
y=\frac{2x^{2}}{3}-\frac{4}{3x}
Divide 4-2x^{3} by -3x.
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