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x\left(2x^{2}-17x+15\right)
Factor out x.
a+b=-17 ab=2\times 15=30
Consider 2x^{2}-17x+15. Factor the expression by grouping. First, the expression needs to be rewritten as 2x^{2}+ax+bx+15. To find a and b, set up a system to be solved.
-1,-30 -2,-15 -3,-10 -5,-6
Since ab is positive, a and b have the same sign. Since a+b is negative, a and b are both negative. List all such integer pairs that give product 30.
-1-30=-31 -2-15=-17 -3-10=-13 -5-6=-11
Calculate the sum for each pair.
a=-15 b=-2
The solution is the pair that gives sum -17.
\left(2x^{2}-15x\right)+\left(-2x+15\right)
Rewrite 2x^{2}-17x+15 as \left(2x^{2}-15x\right)+\left(-2x+15\right).
x\left(2x-15\right)-\left(2x-15\right)
Factor out x in the first and -1 in the second group.
\left(2x-15\right)\left(x-1\right)
Factor out common term 2x-15 by using distributive property.
x\left(2x-15\right)\left(x-1\right)
Rewrite the complete factored expression.