Factor
2\left(x-4\right)\left(x^{2}+4x+16\right)
Evaluate
2\left(x^{3}-64\right)
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2\left(x^{3}-64\right)
Factor out 2.
\left(x-4\right)\left(x^{2}+4x+16\right)
Consider x^{3}-64. Rewrite x^{3}-64 as x^{3}-4^{3}. The difference of cubes can be factored using the rule: a^{3}-b^{3}=\left(a-b\right)\left(a^{2}+ab+b^{2}\right).
2\left(x-4\right)\left(x^{2}+4x+16\right)
Rewrite the complete factored expression. Polynomial x^{2}+4x+16 is not factored since it does not have any rational roots.
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