Solve 2x^3+kx^2-11x+60=0

$$2 x ^ { 3 } + k x ^ { 2 } - 11 x + 60 = 0$$

Solve for k

$$k=\frac{-2x^{3}+11x-60}{x^{2}}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Subtract 2x^{3} from both sides. Anything subtracted from zero gives its negation.

$$kx^{2}-11x+60=-2x^{3}$$

Add 11x to both sides.

$$kx^{2}+60=-2x^{3}+11x$$

Subtract 60 from both sides.

$$kx^{2}=-2x^{3}+11x-60$$

The equation is in standard form.

$$x^{2}k=-2x^{3}+11x-60$$

Divide both sides by x^{2}.

$$\frac{x^{2}k}{x^{2}}=\frac{-2x^{3}+11x-60}{x^{2}}$$

Dividing by x^{2} undoes the multiplication by x^{2}.

$$k=\frac{-2x^{3}+11x-60}{x^{2}}$$

Divide -2x^{3}+11x-60 by x^{2}.

$$k=-2x+\frac{11x-60}{x^{2}}$$