Solve for y
y=-\frac{2\left(x^{3}-2\right)}{9x}
x\neq 0
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9xy=4-2x^{3}
Subtract 2x^{3} from both sides.
\frac{9xy}{9x}=\frac{4-2x^{3}}{9x}
Divide both sides by 9x.
y=\frac{4-2x^{3}}{9x}
Dividing by 9x undoes the multiplication by 9x.
y=-\frac{2x^{2}}{9}+\frac{4}{9x}
Divide 4-2x^{3} by 9x.
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