Solve 2x^3+4x^3*5x-2x*(-x^2)=

$$2 x ^ { 3 } + 4 x ^ { 3 } \cdot 5 x - 2 x \cdot ( - x ^ { 2 } ) =$$

Evaluate

$$4\left(5x+1\right)x^{3}$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 3 and 1 to get 4.

$$2x^{3}+4x^{4}\times 5-2x\left(-x^{2}\right)$$

Multiply 4 and 5 to get 20.

$$2x^{3}+20x^{4}-2x\left(-x^{2}\right)$$

To multiply powers of the same base, add their exponents. Add 1 and 2 to get 3.

$$2x^{3}+20x^{4}-2x^{3}\left(-1\right)$$

Multiply -2 and -1 to get 2.

$$2x^{3}+20x^{4}+2x^{3}$$

Combine 2x^{3} and 2x^{3} to get 4x^{3}.

$$4x^{3}+20x^{4}$$

Factor

$$4\left(5x+1\right)x^{3}$$

Solution Steps

Factor out 2.

$$2\left(x^{3}+10x^{3}x+xx^{2}\right)$$

Consider x^{3}+10x^{4}+x^{3}. Factor out x^{3}.

$$x^{3}\left(2+10x\right)$$

Consider 1+10x+1. Multiply and combine like terms.

$$10x+2$$

Consider 10x+2. Factor out 2.

$$2\left(5x+1\right)$$

Rewrite the complete factored expression.

$$4x^{3}\left(5x+1\right)$$

Simplify.

$$4\left(5x+1\right)x^{3}$$